A) 9 cm |
B) 12 cm |
C) 18 cm |
D) 3 cm |
B) 12 cm |
Perimeter of square = 72 cm
Perimeter of rectangle
=\( \Large \frac{72}{2} \)=36 cm
=> \( \Large 2\times (l+b) \)=36
[l and b are dimension of rectangle]
\( \Large 2\times (12+b) \)=36
=> 12 + b = 18
b=18-12=6cm
And side of square = \( \Large \frac{72}{4} \)=18
Difference between breadth of rectangle and side of the square
= 18 - 6 = 12 cm.