A) 2.50% |
B) 3% |
C) 4% |
D) 5 |
C) 4% |
Given, \( \Large T_{1} \) =\( \Large 2\frac{1}{2} \)yr, \( \Large T_{2} \) = 4 yr
According to the question,
\( \Large \left( P+ \frac {P\times R\times 4}{100}\right) \)-\( \Large \left(P+\frac{P\times R\times 2.5}{100}\right) =1067.20-1012=55.2\)
=> \( \Large \frac{1.5PR}{100} \)=55.2
=> PR=\( \Large \frac{552\times 100}{15} \)=3680
For 4yr,
SI=\( \Large \frac{PRT}{100}=\frac{3680\times 4}{100} \)=RS.147.2
Sum (P)=1067.2 - 147.2=RS.920
We have, PR = 3680
R = \( \Large \frac{3680}{P}=\frac{3680}{920} \) = 4%