A) \( \Large 46\frac{5}{3}% \) |
B) \( \Large 46\frac{2}{3} %\) |
C) \( \Large 46\frac{5}{8} %\) |
D) \( \Large 46\frac{11}{12}% \) |
B) \( \Large 46\frac{2}{3} %\) |
Let sum = p
Then, after 15 yr,
Sum = 8P
SI = 8P-P = 7P
Now, 7P = \( \Large \frac{P\times R\times 15}{100} \)
=> 7 = \( \Large \frac{15R}{100} = \frac{3R}{20} \)
R = \( \Large \frac{20\times 7}{3} \)
= \( \Large \frac{140}{3} \) = \( \Large 46\frac{2}{3}% \)