A) 4 |
B) 6 |
C) 8 |
D) 12 |
B) 6 |
Column I
\( \left(7 \times 8 \times 2\right) = 112 \) = bottom left number
Column II
\( \left(5 \times 4 \times 8\right) = 160 \) = bottom middle number
Column III
\( \left(3 \times 9 \times ?\right) = 0 \) = bottom right number
\( ? = \frac{162}{3 \times 9} = 6 \)
Therefore, ? = 6.