A) \( 68 ^{\circ} \) |
B) \( 72 ^{\circ} \) |
C) \( 102 ^{\circ} \) |
D) \( 65 ^{\circ} \) |
A) \( 68 ^{\circ} \) |
Let the two supplementary angles (sum of 2 angles is equal to \(180 ^{\circ} \)) be A and B
A + B = 180\( ^{\circ} \) and A - B = 44 \( given \)
Therefore, 2A = 224
=> A = \( 112 ^{\circ} \) => B = \( 68 ^{\circ} \)