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If \( \Large x +\frac{1}{x}=2 \), then the value of \( \Large x^{12}-\frac{1}{x^{12}} \) is :

A) 2
B) 0
C) -4
D) 4

Correct Answer:


B) 0

Description for Correct answer:

Given : \( \Large x+\frac{1}{x}=2 \)

=> \( \Large x^{2}+1 = 2x \)

=> \( \Large x^{2}-2x+1 = 0 \)

=> \( \Large \left(x-1\right)^{2} = 0 \)

Put x = 1 in \( \Large x^{12} - \frac{1}{x^{12}} we get \)

\( \Large 1 - \frac{1}{1} = 1 - 1 = 0 \)

Part of solved SSC Practice test(1) questions and answers : Exams >> SSC Exams >> SSC Practice test(1)

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