The sum of 5 consecutive Odd numbers of set-A is 185. What will be the average of Set-B, containing 4 consecutive even numbers, if the smallest number of SetB is 13 more than the highest number of 5 Set-A ?
Correct Answer: Description for Correct answer:
For Set-A
x+x+2+x+4+x+6+x+8 = 185
5x + 20 = 185
5x = 165
x = 33
Set-A = 33, 35, 37, 39, 41
The smallest number of Set-B = 41 +13 = 54
For Set-B,
Required average \( = \frac{54+56+58+60}{4} = 57 \)
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