The ratio of the ages of A and B seven years ago was 3 : 4 respectively. The ratio of their ages nine years from now will be 7 : 8 respectively. What is B's age at present?
Correct Answer: Description for Correct answer:
Let the common ratio be = x
Therefore the present age of A be = 3x + 7
Similarly the present age of B be = 4x + 7
According to the question,
\( \Large \frac{3x + 7 + 9}{4x + 7 + 9} \) = \( \Large \frac{7}{8} \)
\( \Large \frac{3x + 16}{4x + 16} \) = \( \Large \frac{7}{8} \)
24x + 12 8 = 28x + 112
4x = 16
=> x = 4
Present age of B = 4x + 7 = 4 x 4 + 7
= 16 + 7 = 23 years
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