Renu sold article A at a loss of 10%. She sold article B at a price which was 25% more than the selling price of article A. If she made a profit of 20% on article B, by what percent is the cost price of article A more than that of article B ?
Correct Answer: | A) \( \Large 6\dfrac{2}{3} \) |
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Description for Correct answer:
Let cost price of article A = Rs.x
Selling price of article A = \( \Large x \times \dfrac{90}{100}\)= Rs.\( \Large \dfrac{9x}{10}\)
Selling price of article B = \( \Large \dfrac{9x}{10} \times \dfrac{125}{100} = Rs. \dfrac{9x}{8}\)
Cost price of article B = \( \Large \dfrac{9x}{8} \times \dfrac{100}{120} = \dfrac{15x}{16}\)
Required percentage = \( \Large \dfrac{x-\dfrac{15x}{16}}{\dfrac{15x}{16}} \times 100\)
= \( \Large \dfrac{x}{16} \times \dfrac{16}{15x} \times 100\)
= \( \Large \dfrac{20}{3} = 6\dfrac{2}{3}\)
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