A can do a work in 12 days. When he had worked for 3 days, B joined him. If they complete the work in 3 more days, in how many days can B alone finish the work ?
Correct Answer: Description for Correct answer:
A's one day's work = \( \Large \frac{1}{12} \)
A's three day's work = \( \Large \frac{1}{12} \) x 3 = \( \Large \frac{1}{4} \)
Remaining work = 1 - \( \Large \frac{1}{4} \) = \( \Large \frac{3}{4} \)
(A + B) complete the \( \Large \frac{3}{4} \) work in = 3 days
(A + B) complete the work in = 3 x \( \Large \frac{4}{3} \) = 4 days
B's one day's work = \( \Large \frac{1}{4} \) - \( \Large \frac{1}{12} \) = \( \Large \frac{3-1}{12} \) = \( \Large \frac{2}{12} \) = \( \Large \frac{1}{6} \)
Hence, B can complete the work in 6 days.
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