Directions (49-53): In these questions, two equations numbered I and II are given.
You have to solve both the equations and
Give answer:
(1) If X > y
(2) If x ≥ y
(3) x < y
(4) If relationship between x and y cannot be determined
(5) If x ≤ y
I.\( \Large 12x^{2} - x - 1 =0 \)
II.\( \Large 20y^{2} - 41y + 20 =0 \)
Correct Answer: Description for Correct answer:
I. \( \Large 12x^{2} - x - 1 = 0 \)
\( \Large 12x^{2} - 4x + 3x - 1 = 0 \)
\( \Large 4x \left(3x -1\right) \left(3x -1\right) =0 \)
\( \Large \left(4x + 1\right) \left(3x - 1\right) = 0 \)
\( \Large x = \frac{-1}{4}, \frac{1}{3} \)
II.\( \Large 20y^{2} - 41y + 20 = 0 \)
\( \Large 20y^{2} - 25y -16y + 20 = 0 \)
\( \Large 50 \left(4y - 5\right) - 4 \left(4y - 5\right)=0 \)
\( \Large \left(5y - 4\right) \left(4y - 5\right) =0 \)
\( \Large y = \frac{4}{5}, \frac{5}{4} \)
Hence, y > x
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