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If p=999, then the value of \( \Large \sqrt[3]{p \left(p^{2}+3p+3\right)+1 } \) is

A) 1000
B) 999
C) 998
D) 1002

Correct Answer:

A) 1000

Description for Correct answer:
\( \Large P = 999 \)

\( \Large \sqrt[3]{p \left(p^{2}+3p+3\right)+1 } \)

=> \( \Large \sqrt[3]{p^{3}+3p^{2}+3p+1} \)

Therefore, \( \Large \sqrt[3]{ \left(p+1\right)^{3} } \)

= \( \Large \sqrt[3]{ \left(999+1\right)^{3} } \)

= \( \Large \sqrt[3]{ \left(1000\right)^{3} } = 1000 \)

Part of solved Elementary Mathematics questions and answers : >> Elementary Mathematics

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