The value of \( \Large \frac{\left(243\right)^{\frac{n}{5}}.3^{2n+1}}{9^{n}.3^{n-1}} \) is
Correct Answer: Description for Correct answer:
\( \Large \frac{ \left(243\right)^{\frac{n}{5}}.3^{2n+1} }{9^{n}.3^{n-1}} = \frac{ \left(3^{5}\right)^{\frac{n}{5}}.3^{2n+7} }{3^{2n}.3^{n-1}} \)
= \( \Large \frac{3^{n+2n+1}}{3^{2n+n-1}} = \frac{3^{3n+1}}{3^{3n-1}} = 3^{3n+1-3n+1} \)
= \( \Large 3^{2} = 9 \)
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