If \( \Large x^{x\sqrt{x}}= \left(x\sqrt{x}\right)^{x} \) , the x equals


A) \( \Large \frac{4}{9} \)

B) \( \Large \frac{2}{3} \)

C) \( \Large \frac{9}{4} \)

D) \( \Large \frac{3}{2} \)

Correct Answer:
C) \( \Large \frac{9}{4} \)

Description for Correct answer:
\( \Large x^{x\sqrt{x}} = \left(x\sqrt{x}\right)^{x} \)

\( \Large x^{x\sqrt{x}} = \left(x^{\frac{3}{2}}\right)^{x} \)

\( \Large 3^{x\sqrt{x}} = x^{\frac{3}{2}x} \)

\( \Large \left[ If\ bases\ are\ same\ then\ power\ are\ equal \right] \)

Therefore, \( \Large x\sqrt{x} = \frac{3}{2}x\ or\ \sqrt{x} = \frac{3}{2} \)

\( \Large x = \left(\frac{3}{2}\right)^{2} = \frac{9}{4} \)

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