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If 1 < x < 2, then the value of \( \Large \sqrt{ \left(x-1\right)^{2}+\sqrt{ \left(x-3\right)^{2} } } \) is

A) 1
B) 2
C) 3
D) 2x-4

Correct Answer:


B) 2

Description for Correct answer:
1 < x < 2

\( \Large \sqrt{ \left( x-1 \right)^{2} }+\sqrt{ \left(3-x\right)^{2} } \)

(Square root cancel with square)

Therefore, x - 1 + 3 - x - 2

Part of solved Elementary Mathematics questions and answers : >> Elementary Mathematics

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