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If \( \Large 47.2506=4A+7B+2C+\frac{5}{D}+6E \), then the value of \( \Large 5A+3B+6C+D+3E \) is

A) 53.6003
B) 53.603
C) 153.6003
D) 213.0003

Correct Answer:



C) 153.6003

Description for Correct answer:
\( \Large 47.2506=4A+7B+2C+\frac{5}{D}+6E \)

\( \Large 47.2506=4 \times 10+7 \times 1+2 \times 0.10000+5 \times 0.0100+0 \) \( \Large +6 \times 0.0001 \)

Therefore,\( \Large A=10,\ B=1,\ C=0.1000,\ D=\frac{1}{\frac{1}{100}}=100,\ E=0.0001 \)

Therefore, 5A + 3B + 6C + D + 3E

= \( \Large 5 \times 10+3 \times 1+6 \times 0.1+100+3 \times 0.00001 \)

= 50 + 3 + 0.6 + 100 + 0.0003 = 153.6003

Part of solved Elementary Mathematics questions and answers : >> Elementary Mathematics

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