In the following question two equations numbered I and II are given. You have to solve both the equations and Give answer
I. \( \Large x^{2} \) - 8x + 15 = 0
II. \( \Large y^{2} \) - 3y + 2 = 0
Correct Answer: Description for Correct answer:
I. \( \Large x^{2} \) - 8x + 15 = 0
=> \( \Large x^{2} \) - 5x - 3x + 15 = 0
=> x ( x - 5 ) - 3 ( x - 5 ) = 0
=> ( x - 3 ) ( x - 5 ) = 0
\( \Large \therefore \) x = 3 or 5
II. \( \Large y^{2} \) - 3y + 2 = 0
=> \( \Large y^{2} \) - 2y - y + 2 = 0
=> y ( y - 2 ) - 1 ( y - 2 ) = 0
=> ( y - 1) ( y - 2 ) = 0
y = 1 or 2
Clearly, x > y
Part of solved Linear Equations questions and answers :
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