A) 21 days |
B) 18 days |
C) 24 days |
D) 36 days |
A) 21 days |
Let one man’s one day work be x
Let one boy’s one day work be y
2x+7y=1/14 ... (1)
3x + 8y = 1 /11 ... (2)
Equating (1) & (2), x = 1 / 77 and y = 1/ 154
Hence, the days taken to complete by 8 men and 6 boys
= \( \large \left[ 8\left( \frac{1}{77}\right) + 6\left( \frac{1}{154}\right) \right] \)
=\( \large\frac{16 +6}{154} = \frac{22}{154} = \frac{1}{7} = 7\)days
3 times the work can be completed by 8 men and 6 boys = 3 x 7 = 21 days.