A) 4 : 1 |
B) 1 : 4 |
C) 1 : 2 |
D) 2 : 1 |
A) 4 : 1 |
Let x km distance be covered in y h.
So, speed in first case = \( \Large \frac{x}{y}Km/hr\)
And speed in second case = \( \Large \frac{x/2}{2y} = \frac{x}{4y}Km/hr\)
Required ratio = \( \Large \frac{x}{y}:\frac{x}{4y} = 1 : \frac{1}{4}\)
= 4 : 1