Let the number of students in the sections A,B,C and D be a, b, c and d respectively. Then, total weight of students of section A = 45a
Total weight of students of section B = 50b
Total weight of students of section C = 72c
Total weight of students of section D = 80d
According to the question, Average weight of students of section A and B = 48 kg
\( \large\frac{45a + 50b}{a + b} = 48 \)
= > 45a +50b = 48a + 48b
3a = 2b
15a = 10b
And average weight of students of sections B and C = 60kg
= > 50b +72c = 60 (b +c)
= > 10b = 12c
Now average weight of students of A,B,C,D = 60 kg
45a + 50b +72c + 80d = 60(a + b + c + d)
= > 15a + 10b - 12c - 20d = 0
= > 15a = 20d
= > a : d = 4 : 3