If two pipes function together, the tank will be filled in 12 h. One pipe fills the tank in 10 h faster than the other. How many hours does the faster pipe take to fill up the tank?
Correct Answer: Description for Correct answer:
Let one pipe takes m h to fill the tank.
Then, the other pipe takes \( \Large \left(m-10\right)h \)
According to the question,
Therefore, \( \Large \frac{1}{m}+\frac{1}{ \left(m-10\right) }=\frac{1}{12} \)
=> \( \Large \frac{m-10+m}{m \left(m-10\right) }=\frac{1}{12} \)
=> \( \Large 12 \left(m-10+m\right)=m \left(m-10\right) \)
=> \( \Large m^{2}-34m+120 = 0 \)
=> \( \Large m^{2}-30m-4m+120 = 0 \)
=> \( \Large \left(m-30\right) \left(m-4\right)=0 \)
m = 30 or 4
Faster pipe will take \( \Large \left(30-10\right)h \) = 20 h to fill the tank.
Part of solved Pipes and Cisterns questions and answers :
>> Aptitude >> Pipes and Cisterns