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Three taps A, B and C fill a tank in 20 min, 15 min and 12 min, respectively. If all the taps are opened simultaneously, how long will they take to fill 40% of the tank?

A) 1 min
B) 2 min
C) 3 min
D) 4 min

Correct Answer:


B) 2 min

Description for Correct answer:
Part of the tank filled in 1 min by A, B and C.

= \( \Large \frac{1}{20}+\frac{1}{15}+\frac{1}{12} \)

= \( \Large \frac{3+4+5}{60} = \frac{12}{60} = \frac{1}{5} \)

Therefore, Time taken by A, B and C to fill the tank = 5 min.

Therefore, Time taken by A, B and C to fill 40% of the tank

= 40% of 5 = \( \Large \frac{40}{100} \times 5 \)

Part of solved Pipes and Cisterns questions and answers : >> Aptitude >> Pipes and Cisterns

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Similar Questions

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