In a 100m race, A runs at 5 m/sec. Even if B starts 8 m ahead of A. A wins by 3 sec., What is the speed of B?
Correct Answer: Description for Correct answer:
A runs at 5 m/sec. Hence, she will take \( \Large \frac{100}{5} \) = 20 seconds to run 100m.
B starts 8 m ahead of A. Therefore, when A runs 100 m, B has to run (100 - 8) = 92 m.
Despite the lead B has. A finishes the race 3 seconds ahead of B.
Hence, B takes 20 + 3 = 23 seconds to cover the distance of 92 m.
Therefore, the speed of B = \( \Large \frac{92}{23} \) = 4 m/sec.
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