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The equation of the sides of a triangle are \( \Large x-3y=0.\ 4x+3y=5\ and\ 3x+y=0 \). The lines \( \Large 3x-4y=0 \) passage through

A) the incentre
B) the centroid
C) the orthocentre
D) the circumcentre

Correct Answer:




D) the circumcentre

Description for Correct answer:

Two sides \( \Large x-3y=0\ and\ 3x+y=0 \) are perpendicular to each other. Therefore its orthocentre is the point of intersection of \( \Large x-3y=0 \) i.e. \( \Large \left(0,\ 0\right) \) so, the line \( \Large 3x-4y=0 \) passes through the orthocentre of triangle.

Part of solved Straight lines questions and answers : >> Elementary Mathematics >> Straight lines

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Similar Questions

1). If (-4, -5) is one vertex and \( \Large 7x-y+8=0 \) is one diagonal of a square then the equation of second diagonal is:

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B). \( \Large 2x-3y=7 \)

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