A) 2 : 1 |
B) 8 : 7 |
C) 4 : 3 |
D) 3 : 2 |
B) 8 : 7 |
Given: OM = 8, OP = 4 and OB = 10
\( \Large BM^{2}= OB^{2}-OM^{2}=100-64=36 \)
Therefore, BM = 6.
Then PC = 3
Therefore, Volume of cone OAB
= \( \Large \frac{1}{3} \times \pi \times 6^{2} \times 8 \)
= \( \Large 96\ \pi \)
Volume of cone OCD
=\( \Large \frac{1}{3} \times \pi \times 3^{2} \times 4 = 12\ \pi \)
Volume of frustum ABCD = \( \Large 96 \pi -12 \pi = 84 \pi \)
Required ratio = \( \Large \frac{96 \pi }{84 \pi } = \frac{8}{7} \)