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A solid sphere of radius r is sliced by the planes passing through its centre and perpendicular to each other. The total surface area of each of the pieces so formed is

A) \( \Large \frac{2}{3} \pi r^{2} \)
B) \( \Large 2 \pi r^{2} \)
C) \( \Large \frac{4}{3} \pi r^{2} \)
D) \( \Large \pi r^{2} \)

Correct Answer:


B) \( \Large 2 \pi r^{2} \)

Description for Correct answer:

Surface of one piece consists of sum of one fourth of the surface of the sphere and two semicircular areas.

Surface area of each piece

\( \Large \frac{1}{4}.4 \pi r^{2}+2.\frac{1}{2} \pi r^{2} \)

= \( \Large 2 \pi r^{2} \)

Part of solved Mensuration questions and answers : >> Aptitude >> Mensuration

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