If remainder of the polynomial \( \Large x^{3}+x^{2}+x+a \) when divided by \( \Large \left(x-2\right) \) is zero, then value of a is
Correct Answer: Description for Correct answer:
Remainder = \( \Large 2^{3}+2^{2}+2+a = a+14 \)
Therefore, \( \Large a+14 = 0 \)
=> \( \Large a = -14 \)
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