A) 17 |
B) 15 |
C) 7 |
D) 1 |
A) 17 |
Let \( \Large f \left(x\right) = x^{4}+1 \)
Since \( \Large f \left(x\right) \) is divided by \( \Large \left(x-2\right) \),
therefore remainder = \( \Large \left(2\right)^{4}+1=16+1=17 \)