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For what value of p, is the coefficient of \( \Large x^{2} \) in the product \( \Large \left(2x-1\right) \left(x-k\right) \left(px+1\right) \) equal to 0 and the constant term equal to 2?

A) 2
B) \( \Large \frac{2}{5} \)
C) \( \Large \frac{5}{2} \)
D) 5

Correct Answer:


B) \( \Large \frac{2}{5} \)

Description for Correct answer:
\( \Large \left(2x-1\right) \left(x-k\right) \left(px+1\right) \)

= \( \Large 2px^{3}+ \left(2-2kp-p\right)x^{2}+x \left(kp-2k-1\right)+k \)

According to question

\( \Large 2-2kp-p=0\ and\ k=2 \)

\( \Large 2-4p-p=0 \)

\( \Large p = \frac{2}{5} \)

Part of solved Polynomials questions and answers : >> Elementary Mathematics >> Polynomials

Comments

Similar Questions

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