A) 6 cm |
B) 4 cm |
C) 2 cm |
D) 8 cm |
C) 2 cm |
Given. \( \Large DE \parallel BC \)
Since, \( \Large \triangle ADE - \triangle ABC \)
If any line parallel to one side of triangle divides the other two sides proportionally
Then, \( \Large \frac{AB}{AD} = \frac{AC}{AE} \)
=> \( \Large \frac{12x}{6} = \frac{16}{2x} \)
=> \( \Large x^{2} = \frac{16 \times 6}{12 \times 2} = 4 \)
\( \Large x = 2 cm \)