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In a \( \Large \triangle ABC \), if \( \Large \angle A \) = 115 degree, \( \Large \angle C \) = 20 degree and D is a point on BC such that \( \Large AD \perp BC \) and BD = 7 cm, then AD is of length

A) 15 cm
B) 5 cm
C) 7 cm
D) 10 cm

Correct Answer:



C) 7 cm

Description for Correct answer:

\( \Large \triangle ABC \)

\( \Large \angle A = 115 ^{\circ}, \angle C = 20 ^{\circ} \)

\( \Large \therefore \angle B = 180 ^{\circ} - \left(115 ^{\circ} +20 ^{\circ} \right) = 45 ^{\circ} \)

Now, in \( \Large \triangle ABD \)

\( \Large \frac{AD}{BD} = \tan 45 ^{\circ} \)

=> AD = BD = 7 cm

Part of solved Geometry questions and answers : >> Elementary Mathematics >> Geometry

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