A) Rs.1000 |
B) Rs.12000 |
C) Rs.13200 |
D) Rs.11880 |
B) Rs.12000 |
Let principal at the end of first year be Rs.x.
Then, \( \Large \frac{x \times 10 \times 1}{100} = 1320 \)
= x = 13200
Let original principal be Rs.P. Then
amount after 1 year = \( \Large P + \frac{P \times 10 \times 1}{100} = \frac{11P}{10}\)
Therefore, \( \Large \frac{11P}{10} = \) 13200
P = \( \Large \frac{13200 \times 10}{11} \) = Rs.12000.