A) RS.1250 |
B) RS.1200 |
C) RS.1300 |
D) RS.1260 |
A) RS.1250 |
Using the formula, A = \( \Large P \left( 1+ \frac{R}{100}\right)^{n} \)
=> 1352=\( \Large P \left(1+\frac{4}{100} \right)^{2} \)
=> 1352=\( \Large P(1.04)^{2} \)
P=\( \Large \frac{1352}{(1.04)^{2}} \)=RS.1250