A motorboat can travel at 10 km/h in still water. It travelled 91km downstream in a river and then returned to the same place, taking altogether 20 h. The rate of flow of river is
Correct Answer: Description for Correct answer:
Given, speed of boat = 10 km/h
Let speed of flow of river = x km/h
Upstream speed of boat = (10 - x) km/h
and downstream speed of boat
According to question,
= (10 + x) km/h
\( \Large \frac{91}{10-x}+\frac{91}{10+x}=20 \)
\( \Large \frac{91 \left(10+x+10-x\right) }{ \left(10-x\right) \left(10+x\right) } = 20 \)
\( \Large \frac{91 \left(20\right) }{100-x^{2}} = x^{2}-9 \)
x = 3
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