A) 80 |
B) 100 |
C) 120 |
D) 140 |
B) 100 |
Here, n = 120, a = 35, x = 39, y =15
Number of students passed = \( \Large \frac{n \left(a-y\right)}{x-y} \)
= \( \Large \frac{120 \left(35-15\right) }{39-15} = \frac{120 \times 20}{24} \)
= 100 students passed