The average of four positive integers is 73.5. The highest integer is 108 and the lowest integer is 29. The difference between the remaining two integers is 15. Which of the following is the smaller of the remaining two integers?
Correct Answer: Description for Correct answer:
Let one integer be x.
Other integer = x + 15
According to the question,
\( \Large 9+x+x+15+108 = 4 \times 73.5 \)
= 2x + 152 = 294
= 2x = 294 - 152 = 142
\( \Large x = \frac{142}{42} = 71 \)
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