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If \( \Large x+\frac{1}{X}=1 \), then the value of \( \Large \frac{x^{2}+3x+1}{x^{2}+7x+1} \) is :

A) 2
B) 1
C) \( \Large \frac{1}{2} \)
D) \( \Large \frac{3}{7} \)

Correct Answer:



C) \( \Large \frac{1}{2} \)

Description for Correct answer:

Given : \( \Large x + \frac{1}{x} = 1 \)

To find : \( \Large \frac{x^{2}+3x+1}{x^{2}+7x+1} \)

= \( \Large \frac{ \left(x+\frac{1}{x}\right)+3 }{ \left(x+\frac{1}{x}+7\right) } \)

= \( \Large \frac{1+3}{1+7} = \frac{4}{8} = \frac{1}{2} \)

Part of solved SSC Practice test(1) questions and answers : Exams >> SSC Exams >> SSC Practice test(1)

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