” \( \large 4^{11} \) + \( \large 4^{12} \) + \( \large 4^{13} \) + \( \large 4^{14} \) ” is divisible by


A) 7

B) 14

C) 17

D) 9

Correct Answer:
C) 17

Description for Correct answer:
\( \Large 4^{11} + 4^{12} + 4^{13} + 4^{14} \)

= \( \Large4^{11} \left(1 +4^{1} + 4^{2} + 4^{3}\right) \)

=\( \Large4^{11} \left( 1 + 4 + 16 + 64\right) \)

=\( \Large4^{11} \left( 85\right) \) = \( \Large4^{11} \left( 17 \times 5 \right) \)


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