Length of rectangle is 80% of diagonal of square of area 1225, then find area of rectangle, if its perimeter is \( \Large 94\sqrt{2} \).
Correct Answer: Description for Correct answer:
Area of square = 1225 ,
Side of square = \( \Large \sqrt{1225} = 35 \)
Diagonal of square = \( \Large 35\sqrt{2} \)
Length of rectangle =\( \Large \left(35\sqrt{2}\right) \times \frac{80}{100} = 28\sqrt{2} \)
Perimeter of rectangle =\( \Large 94\sqrt{2} \)
\( \Large 2 \left(28\sqrt{2} + b\right) = 94\sqrt{2} \)
\( \Large b = 47\sqrt{2} - 28\sqrt{2} \)
\( \Large b = 19\sqrt{2} \)
Area of rectangle = \( \Large 28\sqrt{2} \times 19\sqrt{2} = 1064 \)
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