Out of 5 men and 3 women, a committee of 3 members is to be formed so that it has 1 woman and 2 men. In how many different ways can it be done?
Correct Answer: Description for Correct answer:
Number of selections = Number of ways of selecting 2 men out of 5 men x number of ways of selecting l woman out of 3 women.
= \( \Large 5_{C_{2}} \times 3_{C_{1}} = \frac{5 \times 4}{1 \times 2} \times 3 = 30 \)
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