Simplify: \( \Large \left[ \frac{\frac{3}{2+\sqrt{3}}-\frac{2}{2-\sqrt{3}}}{2-5\sqrt{3}} \right]\)
Correct Answer: Description for Correct answer:
\( \Large \left[ \frac{\frac{3}{2+\sqrt{3}}-\frac{2}{2-\sqrt{3}}}{2-5\sqrt{3}} \right]\)
=\( \Large \frac{\frac{3 \left(2-\sqrt{3}\right)-2 \left(2+\sqrt{3}\right) }{ \left(2+\sqrt{3}\right) \left(2-\sqrt{3}\right) }}{2-5\sqrt{3}}\)
=\( \Large \frac{6-3\sqrt{3}-4-2\sqrt{3}}{ \left(2+\sqrt{3}\right) \left(2-\sqrt{3}\right) \left(2-5\sqrt{3}\right) }\)
=\( \Large \frac{2-5\sqrt{3}}{2-5\sqrt{3}} = 1 \)
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