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In climbing a 21 m long round pole, a monkey climbs 6 m in the first minute and slips 3 m in the next minute. What time (in minutes) the monkey would take to reach the top of the pole?


A) 11

B) 14

C) \( \Large 14 \frac{2}{3} \)

D) 9

Correct Answer:
A) 11

Description for Correct answer:
Net distance travelled by monkey in 2 min = 3 m

\( \Large \therefore \) In 10 min, distance travelled (climbed) = 15 m

As, it is given in the question that in first minute it climbs 6 m and in other minute it slips down 3 m.

And this happens alternately.

Hence, monkey will travel remaining 6 m in next minute.

\( \Large \therefore \) Total time taken = (10 + 1) = 11 min

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