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Pipes A and B can fill a tank in 5 and 6 h respectively. Pipe C can empty it in 12 h. The tank is half full. All the three pipes are in operation simultaneously. After how much lime the tank will be full?

A) \( \Large 3 \frac{9}{17} h \)
B) 11 h
C) \( \Large 2 \frac{8}{11} h \)
D) \( \Large 1 \frac{13}{17} h \)

Correct Answer:




D) \( \Large 1 \frac{13}{17} h \)

Description for Correct answer:
In one hour work done by all the pipes together

\( \Large = \frac{1}{5} + \frac{1}{6} - \frac{1}{12} \)

\( \Large = \frac{17}{60} \)

In other words, tank is filled by all the pipes working together in \( \Large \frac{60}{17} \) h.

\( \Large \therefore \frac{1}{2} \) tank will be filled by all the pipes working together in \( \Large \frac{60}{17} \times \frac{1}{2} \)

i.e., \( \Large 1\frac{13}{17} h \).

Part of solved Aptitude questions and answers : >> Aptitude

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