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A 10 metre, long ladder is placed against a wall. It is inclined at an angle of \( \Large 30 ^{\circ} \) to the ground. The distance of the foot of the ladder from the wall is
Correct Answer:
Description for Correct answer:
AB is ladder.
\( \Large \angle ABC = 30^{\circ} \)
AC is a wall.
\( \Large \cos 30^{\circ} = \frac{BC}{AB} \)
=> \( \Large \frac{\sqrt{3}}{2} = \frac{BC}{10} \)
=> \( \Large BC = 10 \times \frac{\sqrt{3}}{2} \)
= \( \Large 5 \sqrt{3} \ metre \)
= \( \Large 5 \times 1.732 = 8.66 \ metre \)
AB is ladder.
\( \Large \angle ABC = 30^{\circ} \)
AC is a wall.
\( \Large \cos 30^{\circ} = \frac{BC}{AB} \)
=> \( \Large \frac{\sqrt{3}}{2} = \frac{BC}{10} \)
=> \( \Large BC = 10 \times \frac{\sqrt{3}}{2} \)
= \( \Large 5 \sqrt{3} \ metre \)
= \( \Large 5 \times 1.732 = 8.66 \ metre \)
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