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In the fo1lowing question two equations numbered I and II are given. You have to solve both the equations and Give answer

I. \( \Large \sqrt{361} x + \sqrt{16} \) = 0

II. \( \Large \sqrt{441} \) y + 4 = 0


A) x > y

B) x \( \Large \geq \) y

C) x < y

D) x \( \Large \leq \) y

Correct Answer:
C) x < y

Description for Correct answer:
I. 19x + 4 = 0

=> 19x = -4

=> x = \( \Large \frac{-4}{19} \)

II. 21y + 4 = 0

=> y = \( \Large \frac{-4}{21} \)

Part of solved Linear Equations questions and answers : >> Aptitude >> Linear Equations




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