Topics
In the fo1lowing question two equations numbered I and II are given. You have to solve both the equations and Give answer
I. \( \Large \frac{7}{\sqrt{x}} \) + \( \Large \frac{5}{\sqrt{x}} \) = \( \Large \sqrt{x} \)
II. \( \Large y^{2} \) - \( \Large \frac{(12)^{\frac{5}{2}}}{\sqrt{y}} \) = 0
|
A) x > y |
|
B) x \( \Large \geq \) y |
|
C) x < y |
|
D) x = y or the relationship Cannot be established |
Correct Answer:
| D) x = y or the relationship Cannot be established |
Description for Correct answer:
I. \( \Large \frac{7}{\sqrt{x}} + \frac{5}{\sqrt{x}} = \sqrt{x} \)
=> 7 + 5 = \( \Large \sqrt{x} \times \sqrt{x} \)
=> x = 12
II. \( \Large y^{2} - \frac{(12)^{\frac{5}{2}}}{\sqrt{y}} = 0 \)
=> \( \Large y^{2 + \frac{1}{2}} - (12)^{\frac{5}{2}} = 0 \)
=> \( \Large y^{\frac{5}{2}} = 12^{\frac{5}{2}} \)
=> y = 12
I. \( \Large \frac{7}{\sqrt{x}} + \frac{5}{\sqrt{x}} = \sqrt{x} \)
=> 7 + 5 = \( \Large \sqrt{x} \times \sqrt{x} \)
=> x = 12
II. \( \Large y^{2} - \frac{(12)^{\frac{5}{2}}}{\sqrt{y}} = 0 \)
=> \( \Large y^{2 + \frac{1}{2}} - (12)^{\frac{5}{2}} = 0 \)
=> \( \Large y^{\frac{5}{2}} = 12^{\frac{5}{2}} \)
=> y = 12
Part of solved Linear Equations questions and answers : >> Aptitude >> Linear Equations
Comments
Similar Questions
