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There was 120 litres of pure milk in a vessel. Some quantity of milk was taken out and replaced with 23 litres of water in such a way that the resultant ratio between the quantities of milk and water in the mixture was 4 : 1 respectively. Again 231itres of the mixture was taken out and replaced with 27 litres of water. What is the respective ratio of milk and water in the resultant mixture?

A) 58 : 37
B) 116 : 69
C) 69 : 43
D) 368 : 227

Correct Answer:




D) 368 : 227

Description for Correct answer:
Let x litres of milk was taken out firstly.

Therefore, \( \Large \frac{120-x}{23}=\frac{4}{1} \)

=> 120 - x = 92

=> x - 120 - 92 = 28 Litres

Therefore, Quantity of milk = 120 - 28 = 92 litres

Quantity of water = 23 litres

Case II

In 23 litres of mixture,

Milk = \( \Large \frac{4}{5} \times 23 = \frac{92}{5} \) Litres

Water = \( \Large \frac{23}{5} Litres \)

Therefore, Remaining milk = \( \Large 92 - \frac{92}{5} = \frac{460 - 92}{5} \)

=\( \Large \frac{368}{5} \) Litres

Quantity of water = \( \Large 23 - \frac{23}{5}+27 \)

= \( \Large \frac{115-23+135}{5} = \frac{227}{5} \)Litres

Therefore, Required ratio = \( \Large \frac{368}{5} : \frac{227}{5} \) = 368 : 227

Part of solved Mixture and Allegation questions and answers : >> Aptitude >> Mixture and Allegation

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Similar Questions

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