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If the volume and curved surface area of a cylinder are 616 m3 and 352 m2 respectively, what is the total surface area of the cylinder? (in m2)
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A) 429 |
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B) 419 |
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C) 435 |
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D) 421 |
|
E) 417 |
Correct Answer:
| A) 429 |
Description for Correct answer:
Volume of cylinder = \( \large \pi r^{2}h \)
Curved surface area of cylinder = \( \large 2 \pi rh \)
\( \large \frac{\pi r^{2}h}{2 \pi rh} = \frac{616}{352} \)
r=2 x1.75
r = 3.5 m
\( \large \pi r^{2}h = 616\)
\( \large h = \frac{616}{ \pi \times r^{2} = \frac{616 \times 7}{ 22 \times 3.5 \times 3.5}} \)
h = 16m
Total surface area of the cylinder =
= \( \large 2 \pi r \left( r + h\right) = 22 \times \frac{22}{7} \times 3.5 \left( 3.5 + 16\right) \)
= \( \large 2 x22 x0.5 x19.5=429m^{2}\)
Volume of cylinder = \( \large \pi r^{2}h \)
Curved surface area of cylinder = \( \large 2 \pi rh \)
\( \large \frac{\pi r^{2}h}{2 \pi rh} = \frac{616}{352} \)
r=2 x1.75
r = 3.5 m
\( \large \pi r^{2}h = 616\)
\( \large h = \frac{616}{ \pi \times r^{2} = \frac{616 \times 7}{ 22 \times 3.5 \times 3.5}} \)
h = 16m
Total surface area of the cylinder =
= \( \large 2 \pi r \left( r + h\right) = 22 \times \frac{22}{7} \times 3.5 \left( 3.5 + 16\right) \)
= \( \large 2 x22 x0.5 x19.5=429m^{2}\)
Part of solved IBPS PO-Prelims questions and answers : Exams >> Bank Exams >> IBPS PO-Prelims
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