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TNPSC Question Paper-2013
Struges rule for determining the number of classes (K) in a frequency table is
A) K = 1 + \( 3.32log_{10}N \)
B) K = 1 - \( 3.32log_{10}N \)
C) K = 1 + \( 2.32log_{10}N \)
D) K = 1 + \( 3.32log_{e}N \)
Correct Answer:
A) K = 1 + \( 3.32log_{10}N \)
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