The ages of Harsh and Sumit are 40 Yrs and 60 yr, respectively. How many years before the ratio of their ages was 3:5?


A) 15 yr

B) 20 yr

C) 37 yr

D) 10 Yr

Correct Answer:
D) 10 Yr

Description for Correct answer:
Let x yr before, the ratio of their ages was 3 : 5.

According to the question,
\( \large\frac{40 - x}{60 - x} = \frac{3}{5}\)

200 - 5x = 180 - 3x = 2x => 20

x = 10

Part of solved Problem on ages questions and answers : >> Aptitude >> Problem on ages








Comments

At present,the age of a son is 3/8his father's age.If 12 years ago,the sum of their ages was 42 years .What is the present age of the father ?(in years)
- Srinivas,Rathod





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